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Electrochemistry question

2007 · Q86
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Electrochemistry question

2007 · Q86

NEETChemistryElectrochemistryMCQ+4 / −1
The equilibrium constant of the reaction:
Cu(s) + 2Ag+(aq) →\to→ Cu2+(aq) + 2Ag(s);
Eo = 0.46 V at 298 K is
  1. A
    2.0 ×\times× 1010
  2. B
    4.0 ×\times× 1010
  3. C
    4.0 ×\times× 1015
  4. D
    2.4 ×\times× 1010
View written solutionFree

Correct answer: C

RT ln K = nFE°

ln K = nFE∘RT{{nFE^\circ } \over {RT}}RTnFE∘​

= 2×0.460.0591{{2 \times 0.46} \over {0.0591}}0.05912×0.46​

⇒\Rightarrow⇒ K = 4 ×\times× 1015

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