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Electrochemistry question

2004 · Q89
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Electrochemistry question

2004 · Q89

NEETChemistryElectrochemistryMCQ+4 / −1
The standard e.m.f. of a galvanic cell involving cell reaction with n = 2 is found to be 0.295 V at 25oC. The equilibrium constant of the reaction would be
  1. A
    2.0 ×\times× 1011
  2. B
    4.0 ×\times× 1012
  3. C
    1.0 ×\times× 102
  4. D
    1.0 ×\times× 1010
View written solutionFree

Correct answer: D

We know, from Nernst Equation

Ecell = Eocell - 2.303RTnFlog⁡10K{{2.303RT} \over {nF}}{\log _{10}}KnF2.303RT​log10​K

At equilibrium Ecell = 0

∴\therefore∴ 0 = Eocell - 2.303×8.314×2982×96500log⁡10K{{2.303 \times 8.314 \times 298} \over {2 \times 96500}}{\log _{10}}K2×965002.303×8.314×298​log10​K

⇒\Rightarrow⇒ 0 = 0.295 - 2.303×8.314×2982×96500log⁡10K{{2.303 \times 8.314 \times 298} \over {2 \times 96500}}{\log _{10}}K2×965002.303×8.314×298​log10​K

⇒\Rightarrow⇒ 0.295 = 0.05912log⁡10K{{0.0591} \over 2}{\log _{10}}K20.0591​log10​K

⇒\Rightarrow⇒ log⁡10K{\log _{10}}Klog10​K = 10

⇒\Rightarrow⇒ K = 1 ×\times× 1010

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