NEETChemistryElectrochemistryMCQ+4 / −1
The e.m.f. of a Daniell cell at 298 K is E1.
When the concentration of ZnSO4 is 1.0 M and that of CuSO4 is 0.01 M, the e.m.f. changed to E2. What is the relationship between E1 and E2?
When the concentration of ZnSO4 is 1.0 M and that of CuSO4 is 0.01 M, the e.m.f. changed to E2. What is the relationship between E1 and E2?
- AE1 > E2
- BE1 < E2
- CE1 = E2
- DE2 = 0 E1
View written solutionFree
Correct answer: A
Cell reaction is,
Zn + Cu2+ Zn2+ + Cu
Ecell = Eocell -
Greater the factor , less is the EMF.
Hence E1 > E2
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