NEETChemistryChemical Bonding and Molecular StructureMCQ+4 / −1
In which one of the following species the central atom has the type of hybridization which is not the same as that present in the other three ?
- ASF4
- BI3
- CSbCl52
- DPCl5
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Correct answer: C
The hybridisation of the central atom can be calculated as
H = $${1 \over 2}\left[ \begin{matrix}
\left( \begin{matrix}
No.,of,electrons \
in,valence,shell \
of,atom \\end{matrix} \right) + \left( \begin{matrix}
No.,of,monovalent \
atoms,around \
central,atom \\end{matrix} \right) \
- \left( \begin{matrix}
Ch{\mathop{\rm arge}\nolimits} ,on \
cation \\end{matrix} \right) + \left( \begin{matrix}
Ch{\mathop{\rm arge}\nolimits} ,on \
anion \\end{matrix} \right) \\end{matrix} \right]$$
Applying that formula we find that all the given species except [SbCl5]2- have central atom with sp3d ( corresponding to H = 5) hybridisation. In [SbCl5]2- Sb is sp3d2 hybridized.
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