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Chemical Bonding and Molecular Structure question

2009 · Q115
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Chemical Bonding and Molecular Structure question

2009 · Q115

NEETChemistryChemical Bonding and Molecular StructureMCQ+4 / −1
According to MO theory which of the lists ranks the nitrogen species in terms of increasing bond order ?
  1. A
    N22−<N2−<N2N_2^{2 - } \lt N_2^ - \lt {N_2}N22−​<N2−​<N2​
  2. B
    N2<N22−<N2−{N_2} \lt N_2^{2 - } \lt N_2^ -N2​<N22−​<N2−​
  3. C
    N2−<N22−<N2N_2^ - \lt N_2^{2 - } \lt {N_2}N2−​<N22−​<N2​
  4. D
    N2−<N2<N22−N_2^ - \lt {N_2} \lt N_2^{2 - }N2−​<N2​<N22−​
View written solutionFree

Correct answer: A

According to MOT, the molecular orbital electronic configuration of

N2:(σ1s)2(σ∗1s)2(σ2s)2(σ∗2s)2(π2px)2(π2py)2(π2pz)2{N_2}:{\left( {\sigma 1s} \right)^2}{\left( {{\sigma ^*}1s} \right)^2}{\left( {\sigma 2s} \right)^2}{\left( {{\sigma ^*}2s} \right)^2}{\left( {\pi 2{p_x}} \right)^2}{\left( {\pi 2{p_y}} \right)^2}{\left( {\pi 2{p_z}} \right)^2}N2​:(σ1s)2(σ∗1s)2(σ2s)2(σ∗2s)2(π2px​)2(π2py​)2(π2pz​)2

∴\therefore∴ B.O = 10−42=3{{10 - 4} \over 2} = 3210−4​=3

N2−:(σ1s)2(σ∗1s)2(σ2s)2(σ∗2s)2(π2px)2(π2py)2(π2pz)2(π∗2px)1{N_2}^ - :{\left( {\sigma 1s} \right)^2}{\left( {{\sigma ^*}1s} \right)^2}{\left( {\sigma 2s} \right)^2}{\left( {{\sigma ^*}2s} \right)^2}{\left( {\pi 2{p_x}} \right)^2}{\left( {\pi 2{p_y}} \right)^2}{\left( {\pi 2{p_z}} \right)^2}{\left( {{\pi ^*}2{p_x}} \right)^1}N2​−:(σ1s)2(σ∗1s)2(σ2s)2(σ∗2s)2(π2px​)2(π2py​)2(π2pz​)2(π∗2px​)1

∴\therefore∴ B.O = 10−52=2.5{{10 - 5} \over 2} = 2.5210−5​=2.5

N22−:(σ1s)2(σ∗1s)2(σ2s)2(σ∗2s)2(π2px)2(π2py)2(π2pz)2(π∗2px)1(π∗2py)1{N_2}^{2 - }:{\left( {\sigma 1s} \right)^2}{\left( {{\sigma ^*}1s} \right)^2}{\left( {\sigma 2s} \right)^2}{\left( {{\sigma ^*}2s} \right)^2}{\left( {\pi 2{p_x}} \right)^2}{\left( {\pi 2{p_y}} \right)^2}{\left( {\pi 2{p_z}} \right)^2}{\left( {{\pi ^*}2{p_x}} \right)^1}{\left( {{\pi ^*}2{p_y}} \right)^1}N2​2−:(σ1s)2(σ∗1s)2(σ2s)2(σ∗2s)2(π2px​)2(π2py​)2(π2pz​)2(π∗2px​)1(π∗2py​)1

∴\therefore∴ B.O = 10−62=2{{10 - 6} \over 2} = 2210−6​=2

Hence the order : N22−N_2^{2-}N22−​ < N2−N_2^-N2−​ < N2N_2N2​

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