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Simple Harmonic Motion question

2022 · 27 Jun · Shift 2 · Q54
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  5. /2022 · 27 Jun · Shift 2 · Q54

Simple Harmonic Motion question

2022 · 27 Jun · Shift 2 · Q54

JEE MainPhysicsSimple Harmonic MotionMCQ+4 / −1
The equation of a particle executing simple harmonic motion is given by x=sin⁡π(t+13)mx = \sin \pi \left( {t + {1 \over 3}} \right)mx=sinπ(t+31​)m. At t = 1s, the speed of particle will be (Given : π\piπ = 3.14)
  1. A
    0 cm s −-− 1
  2. B
    157 cm s −-− 1
  3. C
    272 cm s −-− 1
  4. D
    314 cm s −-− 1
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