JEE MainPhysicsSimple Harmonic MotionNumerical+4 / −1
A body is performing simple harmonic with an amplitude of 10 cm. The velocity of the body was tripled by air jet when it is at 5 cm from its mean position. The new amplitude of vibration is cm. The value of x is .
Numerical answer
More from Simple Harmonic Motion
- The motion of a simple pendulum executing S.H.M. is represented by the following equation. , where time is measured in second. The length of pendulum is2022 · MCQ
- A mass of 5 kg is connected to a spring. The potential energy curve of the simple harmonic motion executed by the system is shown in the figure. A simple pendulum of length 4 m has the same period of oscillation as the spring system. What… Includes diagram2021 · MCQ
- Time period of a simple pendulum is T inside a lift when the lift is stationary. If the lift moves upwards with an acceleration g/2, the time period of pendulum will be :2021 · MCQ
- For what value of displacement the kinetic energy and potential energy of a simple harmonic oscillation become equal ?2021 · MCQ
- Consider two identical springs each of spring constant k and negligible mass compared to the mass M as shown. Fig. 1 shows one of them and Fig. 2 shows their series combination. The ratios of time period of oscillation of the two SHM is… Includes diagram2021 · Numerical
- Two particles A and B of equal masses are suspended from two massless springs of spring constants K1 and K2 respectively. If the maximum velocities during oscillations are equal, the ratio of the amplitude of A and B is2021 · MCQ
- A particle performs simple harmonic motion with a period of 2 second. The time taken by the particle to cover a displacement equal to half of its amplitude from the mean position is s. The value of 'a' to the nearest integer…2021 · Numerical
- The time period of a simple pendulum is given by . The measured value of the length of pendulum is 10 cm known to a 1mm accuracy. The time for 200 oscillations of the pendulum is found to be 100 second using a…2021 · MCQ