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Simple Harmonic Motion question

2022 · 25 Jul · Shift 1 · Q49
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  5. /2022 · 25 Jul · Shift 1 · Q49

Simple Harmonic Motion question

2022 · 25 Jul · Shift 1 · Q49

JEE MainPhysicsSimple Harmonic MotionMCQ+4 / −1
JEE Main 2022 (Online) 25th July Morning Shift Physics - Simple Harmonic Motion Question 57 English In figure (A)(\mathrm{A})(A), mass '2 m’ 2 \mathrm{~m}^{\text {' }}2 m’  is fixed on mass 'm\mathrm{m}m' which is attached to two springs of spring constant k\mathrm{k}k. In figure (B), mass 'm\mathrm{m}m' is attached to two springs of spring constant 'k\mathrm{k}k' and '2k′2 \mathrm{k}^{\prime}2k′. If mass 'm\mathrm{m}m' in (A) and in (B) are displaced by distance 'x′x^{\prime}x′ horizontally and then released, then time period T1\mathrm{T}_{1}T1​ and T2\mathrm{T}_{2}T2​ corresponding to (A)(\mathrm{A})(A) and (B) respectively follow the relation.
  1. A
    T1 T2=32\frac{\mathrm{T}_{1}}{\mathrm{~T}_{2}}=\frac{3}{\sqrt{2}} T2​T1​​=2​3​
  2. B
    T1 T2=32\frac{\mathrm{T}_{1}}{\mathrm{~T}_{2}}=\sqrt{\frac{3}{2}} T2​T1​​=23​​
  3. C
    T1 T2=23\frac{\mathrm{T}_{1}}{\mathrm{~T}_{2}}=\sqrt{\frac{2}{3}} T2​T1​​=32​​
  4. D
    T1T2=23\frac{T_{1}}{T_{2}}=\frac{\sqrt{2}}{3}T2​T1​​=32​​
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