Sign in
12thPass logo
New chatPYQ LibraryDoubtsRank report
Sign in to see Recents

Your guest activity stays on this device

Sign in to save progress →
Sign in

Motion in A Straight Line question

2023 · 30 Jan · Shift 2 · Q45
Guest · filters and generic practice availableBrowsing as a guest · PYQ filters and generic practice are available. Sign in only for personalised features and saved progress.
  1. PYQ Library
  2. /JEE Main
  3. /Physics
  4. /Motion in A Straight Line
  5. /2023 · 30 Jan · Shift 2 · Q45

Motion in A Straight Line question

2023 · 30 Jan · Shift 2 · Q45

JEE MainPhysicsMotion in A Straight LineMCQ+4 / −1
A vehicle travels 4 km4 \mathrm{~km}4 km with speed of 3 km/h3 \mathrm{~km} / \mathrm{h}3 km/h and another 4 km4 \mathrm{~km}4 km with speed of 5 km/h5 \mathrm{~km} / \mathrm{h}5 km/h, then its average speed is
  1. A
    3.75 km/h3.75 \mathrm{~km} / \mathrm{h}3.75 km/h
  2. B
    4.25 km/h4.25 \mathrm{~km} / \mathrm{h}4.25 km/h
  3. C
    3.50 km/h3.50 \mathrm{~km} / \mathrm{h}3.50 km/h
  4. D
    4.00 km/h4.00 \mathrm{~km} / \mathrm{h}4.00 km/h
View written solutionFree

Correct answer: A

  1. Given:

    • First distance d1=4 kmd_1 = 4\text{ km}d1​=4 km at speed v1=3 km/hv_1 = 3\text{ km/h}v1​=3 km/h
    • Second distance d2=4 kmd_2 = 4\text{ km}d2​=4 km at speed v2=5 km/hv_2 = 5\text{ km/h}v2​=5 km/h
  2. Average speed formula: vavg=Total distanceTotal timev_{\text{avg}} = \frac{\text{Total distance}}{\text{Total time}}vavg​=Total timeTotal distance​

  3. Compute total distance: dtotal=4+4=8 kmd_{\text{total}} = 4 + 4 = 8\text{ km}dtotal​=4+4=8 km

  4. Compute time for each part:

    • Time for first 444 km: t1=d1v1=43 ht_1 = \frac{d_1}{v_1} = \frac{4}{3}\text{ h}t1​=v1​d1​​=34​ h
    • Time for second 444 km: t2=d2v2=45 ht_2 = \frac{d_2}{v_2} = \frac{4}{5}\text{ h}t2​=v2​d2​​=54​ h
  5. Total time: ttotal=43+45=20+1215=3215 ht_{\text{total}} = \frac{4}{3} + \frac{4}{5} = \frac{20+12}{15} = \frac{32}{15}\text{ h}ttotal​=34​+54​=1520+12​=1532​ h

  6. Average speed: vavg=832/15=8×1532=154=3.75 km/hv_{\text{avg}} = \frac{8}{32/15} = 8 \times \frac{15}{32} = \frac{15}{4} = 3.75\text{ km/h}vavg​=32/158​=8×3215​=415​=3.75 km/h

  7. Check options:

    • A: 3.75 km/h3.75\text{ km/h}3.75 km/h ✔️
    • B: 4.25 km/h4.25\text{ km/h}4.25 km/h ✖️
    • C: 3.50 km/h3.50\text{ km/h}3.50 km/h ✖️
    • D: 4.00 km/h4.00\text{ km/h}4.00 km/h ✖️

Therefore, the correct answer is Option A.

PreviousNext

More from Motion in A Straight Line

  • From the top of a tower, a ball is thrown vertically upward which reaches the ground in 6 s. A second ball thrown vertically downward from the same position with the same speed reaches the ground in 1.5 s. A third ball released, from the…2022 · Numerical
  • A car is moving with speed of 150 km/h and after applying the break it will move 27 m before it stops. If the same car is moving with a speed of one third the reported speed then it will stop after…2022 · Numerical
  • A particle is moving in a straight line such that its velocity is increasing at 5 ms − 1 per meter. The acceleration of the particle is ​ ms − 2 at a point where its velocity is 20 ms − 1.2022 · Numerical
  • Two buses P and Q start from a point at the same time and move in a straight line and their positions are represented by XP​(t)=αt+βt2 and XQ​(t)=ft−t2. At what time, both the buses have same velocity?2022 · MCQ
  • A ball of mass 0.5 kg is dropped from the height of 10 m. The height, at which the magnitude of velocity becomes equal to the magnitude of acceleration due to gravity, is ​ m. [Use g = 10 m/s2]2022 · Numerical
  • A ball is projected vertically upward with an initial velocity of 50 ms − 1 at t = 0s. At t = 2s, another ball is projected vertically upward with same velocity. At t = ​ s, second ball will meet the first ball…2022 · Numerical
  • A bullet is shot vertically downwards with an initial velocity of 100 m/s from a certain height. Within 10 s, the bullet reaches the ground and instantaneously comes to rest due to the perfectly inelastic collision.…2022 · MCQ
  • The velocity of the bullet becomes one third after it penetrates 4 cm in a wooden block. Assuming that bullet is facing a constant resistance during its motion in the block. The bullet stops completely after travelling at (4 + x) cm inside…2022 · MCQ