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Heat and Thermodynamics question

2023 · 25 Jan · Shift 2 · Q56
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  5. /2023 · 25 Jan · Shift 2 · Q56

Heat and Thermodynamics question

2023 · 25 Jan · Shift 2 · Q56

JEE MainPhysicsHeat and ThermodynamicsMCQ+4 / −1
The graph between two temperature scales P and Q is shown in the figure. Between upper fixed point and lower fixed point there are 150 equal divisions of scale P and 100 divisions on scale Q. The relationship for conversion between the two scales is given by :- JEE Main 2023 (Online) 25th January Evening Shift Physics - Heat and Thermodynamics Question 128 English
  1. A
    tP100=tQ−180150{{{t_P}} \over {100}} = {{{t_Q} - 180} \over {150}}100tP​​=150tQ​−180​
  2. B
    tP180−tQ−40100{{{t_P}} \over {180}} - {{{t_Q} - 40} \over {100}}180tP​​−100tQ​−40​
  3. C
    tQ150=tP−180100{{{t_Q}} \over {150}} = {{{t_P} - 180} \over {100}}150tQ​​=100tP​−180​
  4. D
    tQ100=tP−30150{{{t_Q}} \over {100}} = {{{t_P} - 30} \over {150}}100tQ​​=150tP​−30​
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