Match List I with List II
| List I | List II | ||
|---|---|---|---|
| A. | Isothermal Process | I. | Work done by the gas decreases internal energy |
| B. | Adiabatic Process | II. | No change in internal energy |
| C. | Isochoric Process | III. | The heat absorbed goes partly to increase internal energy and partly to do work |
| D. | Isobaric Process | IV. | No work is done on or by the gas |
Choose the correct answer from the options given below :
- AA-I, B-II, C-IV, D-III
- BA-II, B-I, C-III, D-IV
- CA-II, B-I, C-IV, D-III
- DA-I, B-II, C-III, D-IV
View written solutionFree
Correct answer: C
-
Use the first law of thermodynamics
where:
- = change in internal energy
- = heat supplied to the gas
- = work done by the gas
-
Match each process
A. Isothermal process
In an isothermal process, temperature remains constant.
For an ideal gas, internal energy depends only on temperature, so
Hence, this matches: II. No change in internal energy
So,
B. Adiabatic process
In an adiabatic process,
Therefore,
So if the gas does work, its internal energy decreases.
Hence, this matches: I. Work done by the gas decreases internal energy
So,
C. Isochoric process
In an isochoric process, volume remains constant, so
Hence, IV. No work is done on or by the gas
So,
D. Isobaric process
In an isobaric process, pressure remains constant.
Heat supplied is used partly to increase internal energy and partly to do work:
Hence, this matches: III. The heat absorbed goes partly to increase internal energy and partly to do work
So,
-
Final matching
A\!-II,\; B\!-I,\; C\!-IV,\; D\!-III
-
Compare with options
This corresponds to Option C.
-
Comparison with stored answer
Stored correct answer = C
Our derived answer = C
So they agree.
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