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Heat and Thermodynamics question

2023 · 30 Jan · Shift 1 · Q48
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  5. /2023 · 30 Jan · Shift 1 · Q48

Heat and Thermodynamics question

2023 · 30 Jan · Shift 1 · Q48

JEE MainPhysicsHeat and ThermodynamicsMCQ+4 / −1
Heat is given to an ideal gas in an isothermal process. A. Internal energy of the gas will decrease. B. Internal energy of the gas will increase. C. Internal energy of the gas will not change. D. The gas will do positive work. E. The gas will do negative work. Choose the correct answer from the options given below :
  1. A
    B and D only
  2. B
    C and E only
  3. C
    A and E only
  4. D
    C and D only
View written solutionFree

Correct answer: D

  1. Key fact for an ideal gas
    For an ideal gas, internal energy depends only on temperature: U=U(T)U = U(T)U=U(T)

  2. Given process: isothermal
    In an isothermal process, temperature remains constant: ΔT=0\Delta T = 0ΔT=0 Therefore, for an ideal gas, ΔU=0\Delta U = 0ΔU=0 So:

  • A. Internal energy decreases →\to→ False
  • B. Internal energy increases →\to→ False
  • C. Internal energy does not change →\to→ True
  1. Use first law of thermodynamics
    First law: Q=ΔU+WQ = \Delta U + WQ=ΔU+W Here heat is given to the gas, so: Q>0Q > 0Q>0 And from isothermal ideal gas process: ΔU=0\Delta U = 0ΔU=0 Hence, W=Q>0W = Q > 0W=Q>0 So the gas does positive work.

Thus:

  • D. The gas will do positive work →\to→ True
  • E. The gas will do negative work →\to→ False
  1. Select the correct combination
    The correct statements are C and D only.

Therefore, the correct option is: D\boxed{\text{D}}D​

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