Sign in
12thPass logo
New chatPYQ LibraryDoubtsRank report
Sign in to see Recents

Your guest activity stays on this device

Sign in to save progress →
Sign in

Heat and Thermodynamics question

2020 · 5 Sep · Shift 1 · Q56
Guest · filters and generic practice availableBrowsing as a guest · PYQ filters and generic practice are available. Sign in only for personalised features and saved progress.
  1. PYQ Library
  2. /JEE Main
  3. /Physics
  4. /Heat and Thermodynamics
  5. /2020 · 5 Sep · Shift 1 · Q56

Heat and Thermodynamics question

2020 · 5 Sep · Shift 1 · Q56

JEE MainPhysicsHeat and ThermodynamicsMCQ+4 / −1
Number of molecules in a volume of 4 cm3 of a perfect monoatomic gas at some temperature T and at a pressure of 2 cm of mercury is close to? (Given, mean kinetic energy of a molecule (at T) is 4 ×\times× 10–14 erg, g = 980 cm/s2, density of mercury = 13.6 g/cm3)
  1. A
    5.8 ×\times× 1018
  2. B
    4.0 ×\times× 1016
  3. C
    5.8 ×\times× 1016
  4. D
    4.0 ×\times× 1018
View written solutionFree

Correct answer: D

  1. Use kinetic theory relation

For a monoatomic ideal gas, the average kinetic energy per molecule is

32kT=4×10−14 erg\frac{3}{2}kT = 4\times 10^{-14}\ \text{erg}23​kT=4×10−14 erg

So,

kT=23×4×10−14=83×10−14 ergkT = \frac{2}{3}\times 4\times 10^{-14} = \frac{8}{3}\times 10^{-14}\ \text{erg}kT=32​×4×10−14=38​×10−14 erg

  1. Use ideal gas equation in molecular form

PV=NkTPV = NkTPV=NkT

Hence,

N=PVkTN = \frac{PV}{kT}N=kTPV​

  1. Convert pressure into cgs units

Given pressure = 222 cm of mercury.

Pressure due to a mercury column:

P=hρgP = h\rho gP=hρg

with

  • h=2 cmh = 2\ \text{cm}h=2 cm
  • ρ=13.6 g/cm3\rho = 13.6\ \text{g/cm}^3ρ=13.6 g/cm3
  • g=980 cm/s2g = 980\ \text{cm/s}^2g=980 cm/s2

Therefore,

P=2×13.6×980P = 2\times 13.6\times 980P=2×13.6×980

P=26656 dyne/cm2P = 26656\ \text{dyne/cm}^2P=26656 dyne/cm2

  1. Volume in cgs units

Given

V=4 cm3V = 4\ \text{cm}^3V=4 cm3

So,

PV=26656×4=106624 ergPV = 26656\times 4 = 106624\ \text{erg}PV=26656×4=106624 erg

(since 1 dyne/cm2×1 cm3=1 dyne⋅cm=1 erg1\ \text{dyne/cm}^2 \times 1\ \text{cm}^3 = 1\ \text{dyne}\cdot\text{cm} = 1\ \text{erg}1 dyne/cm2×1 cm3=1 dyne⋅cm=1 erg)

  1. Calculate number of molecules

N=106624(83×10−14)N = \frac{106624}{\left(\frac{8}{3}\times 10^{-14}\right)}N=(38​×10−14)106624​

N=106624×38×1014N = 106624\times \frac{3}{8}\times 10^{14}N=106624×83​×1014

N=39984×1014N = 39984\times 10^{14}N=39984×1014

N≈3.9984×1018N \approx 3.9984\times 10^{18}N≈3.9984×1018

N≈4.0×1018N \approx 4.0\times 10^{18}N≈4.0×1018

  1. Match with options

This corresponds to:

Option D: 4.0×10184.0\times 10^{18}4.0×1018

PreviousNext

More from Heat and Thermodynamics

  • Three different processes that can occur in an ideal monoatomic gas are shown in the P vs V diagram. The paths are labelled as A → B, A → C and A → D. The change in internal energies during these process are taken as EAB, EAC… Includes diagram2020 · MCQ
  • Nitrogen gas is at 300oC temperature. The temperature (in K) at which the rms speed of a H2 molecule would be equal to the rms speed of a nitrogen molecule, is ​. (Molar mass of N2 gas 28 g).2020 · Numerical
  • In an adiabatic process, the density of a diatomic gas becomes 32 times its initial value. The final pressure of the gas is found to be n times the initial pressure. The value of n is :2020 · MCQ
  • Two different wires having lengths L1 and L2, and respective temperature coefficient of linear expansion α 1 and α 2, are joined end-to-end. Then the effective temperature coefficient of linear expansion is :2020 · MCQ
  • Molecules of an ideal gas are known to have three translational degrees of freedom and two rotational degrees of freedom.The gas is maintained at a temperature of T. The total internal energy, U of a mole of this gas, and the value of γ(=Cv​Cp​​)…2020 · MCQ
  • Initially a gas of diatomic molecules is contained in a cylinder of volume V1 at a pressure P1 and temperature 250 K. Assuming that 25% of the molecules get dissociated causing a change in number of moles. The pressure of the resulting gas…2020 · Numerical
  • Three rods of identical cross-section and lengths are made of three different materials of thermal conductivity K1 , K2 and K3 , respecrtively. They are joined together at their ends to make a long rod (see figure). One end of the long rod… Includes diagram2020 · MCQ
  • In a dilute gas at pressure P and temperature T, the mean time between successive collisions of a molecule varies with T as :2020 · MCQ