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Electronic Devices question

2025 · 4 Apr · Shift 2 · Q69
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Electronic Devices question

2025 · 4 Apr · Shift 2 · Q69

JEE MainPhysicsElectronic DevicesMCQ+4 / −1
Consider a n-type semiconductor in which ne\mathrm{n}_{\mathrm{e}}ne​ and nh\mathrm{n}_{\mathrm{h}}nh​ are number of electrons and holes, respectively. (A) Holes are minority carriers (B) The dopant is a pentavalent atom (C) nenheqni2\mathrm{n}_{\mathrm{e}} \mathrm{n}_{\mathrm{h}} eq \mathrm{n}_i^2ne​nh​eqni2​(where ni\mathrm{n}_ini​ is number of electrons or holes in semiconductor when it is intrinsic form) (D) nenh⩾ni2\mathrm{n}_{\mathrm{e}} \mathrm{n}_{\mathrm{h}} \geqslant \mathrm{n}_i^2ne​nh​⩾ni2​ (E) The holes are not generated due to the donors Choose the correct answer from the options given below :
  1. A
    (A), (B), (E) only
  2. B
    (A), (C), (E) only
  3. C
    (A), (B), (C) only
  4. D
    (A), (C), (D) only
View written solutionFree

Correct answer: NONE OF THE GIVEN OPTIONS IS EXACTLY CORRECT; THE CORRECT SET SHOULD BE (A), (B), (C), AND (E).

  1. Identify properties of an n-type semiconductor

    In an n-type semiconductor, the semiconductor is doped with a pentavalent impurity (donor impurity), such as P, As, or Sb.

    • These donor atoms contribute extra electrons.
    • Hence, electrons are majority carriers.
    • Holes are minority carriers.

    Therefore:

    • (A) Holes are minority carriers  ⇒\,\Rightarrow⇒ True
    • (B) The dopant is a pentavalent atom  ⇒\,\Rightarrow⇒ True
  2. Check statement (C):

    For a semiconductor in thermal equilibrium, the mass action law is nenh=ni2n_e n_h = n_i^2ne​nh​=ni2​ where nin_ini​ is the intrinsic carrier concentration.

    So statement (C) is True.

  3. Check statement (D):

    Statement (D) says nenh≥ni2n_e n_h \geq n_i^2ne​nh​≥ni2​

    But from the mass action law, nenh=ni2n_e n_h = n_i^2ne​nh​=ni2​ exactly, not just greater than or equal to.

    Hence (D) is not taken as correct in this context.

  4. Check statement (E):

    In an n-type semiconductor, donor atoms donate electrons, not holes. The holes present are due to thermal generation, not due to donors.

    Therefore:

    • (E) The holes are not generated due to the donors  ⇒\,\Rightarrow⇒ True
  5. Collect correct statements

    The true statements are: (A),(B),(C),(E)(A), (B), (C), (E)(A),(B),(C),(E)

  6. Compare with given options

    Options are:

    • A: (A),(B),(E)(A), (B), (E)(A),(B),(E) only
    • B: (A),(C),(E)(A), (C), (E)(A),(C),(E) only
    • C: (A),(B),(C)(A), (B), (C)(A),(B),(C) only
    • D: (A),(C),(D)(A), (C), (D)(A),(C),(D) only

    The exact correct combination (A),(B),(C),(E)(A), (B), (C), (E)(A),(B),(C),(E) is not present in the options.

    Among the listed options, option A omits (C), option B omits (B), option C omits (E), and option D includes incorrect (D).

    Since (C) is a standard and correct relation for semiconductors in equilibrium, the stored answer A appears incomplete/incorrect.

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