To obtain the given truth table, following logic gate should be placed at G :

Electronic Devices PYQ — JEE Main 2025 · 22 Jan · Shift 2 · Q59 with Solution

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Correct answer: QUESTION IS INCOMPLETE BECAUSE THE TRUTH TABLE/CIRCUIT DIAGRAM IS MISSING; NO UNIQUE GATE CAN BE IDENTIFIED.

The question asks: which logic gate should be placed at $G$ to obtain the given truth table?

However, the crucial part needed to solve this problem — the truth table (or the circuit diagram showing gate $G$ and the outputs) — is missing from the provided prompt.

Without the truth table or circuit connections, it is not possible to determine uniquely whether $G$ should be:

NOR gate
OR gate
AND gate
NAND gate

Why the answer cannot be determined

For two binary inputs $A$ and $B$ , these gates produce different outputs:

1. OR gate

$Y=A+B$ Truth table:

\begin{array}{c c|c} A & B & Y \\ 0 & 0 & 0 \\ 0 & 1 & 1 \\ 1 & 0 & 1 \\ 1 & 1 & 1 \end{array}

2. AND gate

$Y=AB$ Truth table:

\begin{array}{c c|c} A & B & Y \\ 0 & 0 & 0 \\ 0 & 1 & 0 \\ 1 & 0 & 0 \\ 1 & 1 & 1 \end{array}

3. NOR gate

$Y=\overline{A+B}$ Truth table:

\begin{array}{c c|c} A & B & Y \\ 0 & 0 & 1 \\ 0 & 1 & 0 \\ 1 & 0 & 0 \\ 1 & 1 & 0 \end{array}

4. NAND gate

$Y=\overline{AB}$ Truth table:

\begin{array}{c c|c} A & B & Y \\ 0 & 0 & 1 \\ 0 & 1 & 1 \\ 1 & 0 & 1 \\ 1 & 1 & 0 \end{array}

So the correct option depends entirely on the missing truth table.

Conclusion

Since the truth table is not included, the problem is incomplete and no unique answer can be derived.

Please provide the truth table or the circuit diagram so that the correct gate at $G$ can be identified.

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Why the answer cannot be determined

For two binary inputs

A

and

B

, these gates produce different outputs:

1. OR gate

Y=A+B

Truth table:

\begin{array}{c c|c} A & B & Y \\ 0 & 0 & 0 \\ 0 & 1 & 1 \\ 1 & 0 & 1 \\ 1 & 1 & 1 \end{array}

2. AND gate

Y=AB

Truth table:

\begin{array}{c c|c} A & B & Y \\ 0 & 0 & 0 \\ 0 & 1 & 0 \\ 1 & 0 & 0 \\ 1 & 1 & 1 \end{array}

3. NOR gate

Y=\overline{A+B}

Truth table:

\begin{array}{c c|c} A & B & Y \\ 0 & 0 & 1 \\ 0 & 1 & 0 \\ 1 & 0 & 0 \\ 1 & 1 & 0 \end{array}

4. NAND gate

Y=\overline{AB}

Truth table:

\begin{array}{c c|c} A & B & Y \\ 0 & 0 & 1 \\ 0 & 1 & 1 \\ 1 & 0 & 1 \\ 1 & 1 & 0 \end{array}

So the correct option depends entirely on the missing truth table.

Electronic Devices question

Electronic Devices question

Why the answer cannot be determined

1. OR gate

2. AND gate

3. NOR gate

4. NAND gate

Conclusion

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Electronic Devices question

Electronic Devices question

Why the answer cannot be determined

1. OR gate

2. AND gate

3. NOR gate

4. NAND gate

Conclusion

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