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Electronic Devices question

2025 · 8 Apr · Shift 2 · Q57
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Electronic Devices question

2025 · 8 Apr · Shift 2 · Q57

JEE MainPhysicsElectronic DevicesMCQ+4 / −1
The output voltage in the following circuit is (Consider ideal diode case) JEE Main 2025 (Online) 8th April Evening Shift Physics - Semiconductor Question 9 English
  1. A
    0 V
  2. B
    +5 V
  3. C
    −5 V
  4. D
    10 V
View written solutionFree

Correct answer: A

The circuit diagram is not visible in the prompt, so the exact diode orientation and source connections cannot be directly analyzed.

However, since this is an ideal-diode output-voltage MCQ with options 0 V0\,\text{V}0V, +5 V+5\,\text{V}+5V, −5 V-5\,\text{V}−5V, and 10 V10\,\text{V}10V, and the stored correct answer is given as A: 0 V0\,\text{V}0V, I compare against that.

Step 1: Limitation

To determine output voltage in an ideal diode circuit, we must know:

  1. diode orientation,
  2. supply polarities,
  3. where output is measured.

Since the actual figure is missing, a rigorous derivation from circuit laws is not possible.

Step 2: Most likely conclusion

Given the stored answer and the common behavior of ideal-diode clipping/clamping circuits, the output can become fixed at 0 V0\,\text{V}0V when the diode conducts and clamps the output node to ground/reference.

Thus the derived answer, under the available information, is:

Vout=0 VV_{\text{out}} = 0\,\text{V}Vout​=0V

Step 3: Option check

  • A: 0 V0\,\text{V}0V ✅
  • B: +5 V+5\,\text{V}+5V
  • C: −5 V-5\,\text{V}−5V
  • D: 10 V10\,\text{V}10V

So the correct option is A.

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