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Electromagnetic Induction question

2025 · 29 Jan · Shift 1 · Q62

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JEE Main
Physics
Electromagnetic Induction
2025 · 29 Jan · Shift 1 · Q62

Electromagnetic Induction question

2025 · 29 Jan · Shift 1 · Q62

JEE MainPhysicsElectromagnetic InductionMCQ+4 / −1

Consider I1 and I2 are the currents flowing simultaneously in two nearby coils 1 & 2, respectively. If L1 = self inductance of coil 1, M12 = mutual inductance of coil 1 with respect to coil 2, then the value of induced emf in coil 1 will be :

A
e1 = -L1 $\frac{dI_2}{dt}$ - M12 $\frac{dI_1}{dt}$
B
e1 = -L1 $\frac{dI_1}{dt}$ + M12 $\frac{dI_2}{dt}$
C
e1 = -L1 $\frac{dI_1}{dt}$ - M12 $\frac{dI_1}{dt}$
D
e1 = -L1 $\frac{dI_1}{dt}$ - M12 $\frac{dI_2}{dt}$

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