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Electromagnetic Induction question

2024 · 1 Feb · Shift 2 · Q88
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  5. /2024 · 1 Feb · Shift 2 · Q88

Electromagnetic Induction question

2024 · 1 Feb · Shift 2 · Q88

JEE MainPhysicsElectromagnetic InductionNumerical+4 / −1
A coil of 200 turns and area 0.20 m20.20 \mathrm{~m}^20.20 m2 is rotated at half a revolution per second and is placed in uniform magnetic field of 0.01 T0.01 \mathrm{~T}0.01 T perpendicular to axis of rotation of the coil. The maximum voltage generated in the coil is 2πβ\frac{2 \pi}{\beta}β2π​ volt. The value of β\betaβ is ‾\underline{\hspace{2cm}}​.
Numerical answer
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