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Electromagnetic Induction question

2024 · 29 Jan · Shift 1 · Q74
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  5. /2024 · 29 Jan · Shift 1 · Q74

Electromagnetic Induction question

2024 · 29 Jan · Shift 1 · Q74

JEE MainPhysicsElectromagnetic InductionMCQ+4 / −1

Match List I with List II

List - I List - II
(A) ∮B⃗⋅dl→=μoic+μoεodϕEdt\oint \vec{B} \cdot \overrightarrow{d l}=\mu_o i_c+\mu_o \varepsilon_o \frac{d \phi_E}{d t}∮B⋅dl=μo​ic​+μo​εo​dtdϕE​​ (I) Gauss' law for electricity
(B) ∮E⃗⋅dl→=dϕBdt\oint \vec{E} \cdot \overrightarrow{d l}=\frac{d \phi_B}{d t}∮E⋅dl=dtdϕB​​ (II) Gauss' law for magnetism
(C) ∮E⃗⋅dA→=Qεo\oint \vec{E} \cdot \overrightarrow{d A}=\frac{Q}{\varepsilon_o}∮E⋅dA=εo​Q​ (III) Faraday law
(D) ∮B⃗⋅dA→=0\oint \vec{B} \cdot \overrightarrow{d A}=0∮B⋅dA=0 (IV) Ampere - Maxwell law

Choose the correct answer from the options given below:

  1. A
    A-IV, B-III, C-I, D-II
  2. B
    A-I, B-II, C-III, D-IV
  3. C
    A-IV, B-I, C-III, D-II
  4. D
    A-II, B-III, C-I, D-IV
View written solutionFree

Correct answer: A

  1. Identify each equation in List I

    (A) ∮B⃗⋅dl→=μ0ic+μ0ε0dϕEdt\oint \vec{B}\cdot \overrightarrow{dl}=\mu_0 i_c+\mu_0\varepsilon_0\frac{d\phi_E}{dt}∮B⋅dl=μ0​ic​+μ0​ε0​dtdϕE​​ This is the Ampere-Maxwell law.

    So, A→(IV)A \to \text{(IV)}A→(IV)

  2. Equation (B)

    ∮E⃗⋅dl→=dϕBdt\oint \vec{E}\cdot \overrightarrow{dl}=\frac{d\phi_B}{dt}∮E⋅dl=dtdϕB​​ This is intended to represent Faraday's law of electromagnetic induction.

    Standard form is ∮E⃗⋅dl⃗=−dϕBdt\oint \vec{E}\cdot d\vec{l}=-\frac{d\phi_B}{dt}∮E⋅dl=−dtdϕB​​ The negative sign is usually present by Lenz's law, but clearly this option corresponds to Faraday law.

    So, B→(III)B \to \text{(III)}B→(III)

  3. Equation (C)

    ∮E⃗⋅dA→=Qε0\oint \vec{E}\cdot \overrightarrow{dA}=\frac{Q}{\varepsilon_0}∮E⋅dA=ε0​Q​ This is Gauss' law for electricity.

    So, C→(I)C \to \text{(I)}C→(I)

  4. Equation (D)

    ∮B⃗⋅dA→=0\oint \vec{B}\cdot \overrightarrow{dA}=0∮B⋅dA=0 This is Gauss' law for magnetism.

    So, D→(II)D \to \text{(II)}D→(II)

  5. Final matching

    A ⁣− ⁣IV,  B ⁣− ⁣III,  C ⁣− ⁣I,  D ⁣− ⁣IIA\!-\!IV,\; B\!-\!III,\; C\!-\!I,\; D\!-\!IIA−IV,B−III,C−I,D−II

  6. Compare with options

    This matches Option A.

  7. Comparison with stored correct answer

    Stored correct answer is A, which agrees with the derived answer.

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