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Current Electricity question

2024 · 9 Apr · Shift 1 · Q90
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Current Electricity question

2024 · 9 Apr · Shift 1 · Q90

JEE MainPhysicsCurrent ElectricityNumerical+4 / −1
The current flowing through the 1Ω1 \Omega1Ω resistor is n10\frac{n}{10}10n​ A. The value of nnn is ‾\underline{\hspace{2cm}}​. JEE Main 2024 (Online) 9th April Morning Shift Physics - Current Electricity Question 39 English
Numerical answer
View written solutionFree

Correct answer: 25

The question refers to a circuit diagram, but the diagram is not provided here. Without the actual circuit connections, sources, and resistor arrangement, the current through the 1 Ω1\,\Omega1Ω resistor cannot be derived uniquely from the text alone.

  1. What is missing? To calculate the current through the 1 Ω1\,\Omega1Ω resistor, we need the full circuit diagram showing:

    • how the resistors are connected,
    • the values of all other resistors,
    • battery/emf values and polarities,
    • any internal resistances if present.
  2. What can be inferred from the stored answer? The stored correct answer is 252525, and the current is stated to be n10\dfrac{n}{10}10n​ A.

    So if that stored answer is correct, then n10=2510=2.5 A\frac{n}{10}=\frac{25}{10}=2.5\text{ A}10n​=1025​=2.5 A and hence n=25.n=25.n=25.

  3. Limitation Since the circuit diagram is absent, I cannot independently verify whether n=25n=25n=25 follows from circuit analysis. I can only report that, based on the provided stored answer, the intended value is 252525.

Therefore, the answer consistent with the stored key is: n=25n=25n=25

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