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Current Electricity question

2024 · 27 Jan · Shift 2 · Q80

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JEE Main
Physics
Current Electricity
2024 · 27 Jan · Shift 2 · Q80

Current Electricity question

2024 · 27 Jan · Shift 2 · Q80

JEE MainPhysicsCurrent ElectricityMCQ+4 / −1

Wheatstone bridge principle is used to measure the specific resistance

\left(S_1\right)

of given wire, having length

L

, radius

r

. If

X

is the resistance of wire, then specific resistance is ;

S_1=X\left(\frac{\pi r^2}{L}\right)

. If the length of the wire gets doubled then the value of specific resistance will be :

A
$\frac{S_1}{4}$
B
$2 \mathrm{~S}_1$
C
$\frac{\mathrm{S}_1}{2}$
D
$S_1$

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