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Current Electricity question

2024 · 27 Jan · Shift 2 · Q72
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Current Electricity question

2024 · 27 Jan · Shift 2 · Q72

JEE MainPhysicsCurrent ElectricityMCQ+4 / −1
Three voltmeters, all having different internal resistances are joined as shown in figure. When some potential difference is applied across AAA and BBB, their readings are V1,V2V_1, V_2V1​,V2​ and V3V_3V3​. Choose the correct option. JEE Main 2024 (Online) 27th January Evening Shift Physics - Current Electricity Question 62 English
  1. A
    V1=V2V_1=V_2V1​=V2​
  2. B
    V1eqV3−V2V_1 eq V_3-V_2V1​eqV3​−V2​
  3. C
    V1+V2=V3V_1+V_2=V_3V1​+V2​=V3​
  4. D
    V1+V2>V3V_1+V_2>V_3V1​+V2​>V3​
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