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Center of Mass question

2025 · 29 Jan · Shift 2 · Q51
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Center of Mass question

2025 · 29 Jan · Shift 2 · Q51

JEE MainPhysicsCenter of MassMCQ+4 / −1
JEE Main 2025 (Online) 29th January Evening Shift Physics - Center of Mass and Collision Question 7 English Three equal masses mmm are kept at vertices (A,B,C)(A, B, C)(A,B,C) of an equilateral triangle of side a in free space. At t=0t=0t=0, they are given an initial velocity VA→=V0AC→,VB→=V0BA→\overrightarrow{V_A}=V_0 \overrightarrow{A C}, \overrightarrow{V_B}=V_0 \overrightarrow{B A}VA​​=V0​AC,VB​​=V0​BA and VC→=V0CB→\overrightarrow{V_C}=V_0 \overrightarrow{C B}VC​​=V0​CB. Here, AC→,CB→\overrightarrow{A C}, \overrightarrow{C B}AC,CB and BA→\overrightarrow{B A}BA are unit vectors along the edges of the triangle. If the three masses interact gravitationally, then the magnitude of the net angular momentum of the system at the point of collision is :
  1. A
    12\frac{1}{2}21​ a mV0\mathrm{mV}_0mV0​
  2. B
    3 a mV0\mathrm{mV}_0mV0​
  3. C
    32\frac{3}{2}23​ a mV0\mathrm{mV}_0mV0​
  4. D
    32\frac{\sqrt{3}}{2}23​​ a mV0\mathrm{m}V_0mV0​
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