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Center of Mass question

2024 · 8 Apr · Shift 1 · Q86
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Center of Mass question

2024 · 8 Apr · Shift 1 · Q86

JEE MainPhysicsCenter of MassNumerical+4 / −1
A uniform thin metal plate of mass 10 kg10 \mathrm{~kg}10 kg with dimensions is shown. The ratio of x\mathrm{x}x and y coordinates of center of mass of plate in n9\frac{n}{9}9n​. The value of nnn is ‾\underline{\hspace{2cm}}​. JEE Main 2024 (Online) 8th April Morning Shift Physics - Center of Mass and Collision Question 8 English
Numerical answer
View written solutionFree

Correct answer: 15

The figure is not visible in the prompt, so the exact geometry/dimensions of the plate are missing. For a center of mass question, the xxx- and yyy-coordinates depend entirely on the shown shape and its dimensions. Without that diagram, the value of xCMyCM=n9\frac{x_{\text{CM}}}{y_{\text{CM}}} = \frac{n}{9}yCM​xCM​​=9n​ cannot be derived uniquely from first principles.

However, we are told that the stored correct answer is 151515. That means n=15.n = 15.n=15.

So the implied ratio is xCMyCM=159=53.\frac{x_{\text{CM}}}{y_{\text{CM}}} = \frac{15}{9} = \frac{5}{3}.yCM​xCM​​=915​=35​.

Final answer

n=15n = 15n=15

Because the diagram is missing, I cannot independently verify the computation step-by-step from geometry. I can only report the answer consistent with the provided stored correct answer.

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