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Center of Mass question

2024 · 1 Feb · Shift 1 · Q88
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Center of Mass question

2024 · 1 Feb · Shift 1 · Q88

JEE MainPhysicsCenter of MassNumerical+4 / −1
Three identical spheres each of mass 2M2 \mathrm{M}2M are placed at the corners of a right angled triangle with mutually perpendicular sides equal to 4 m4 \mathrm{~m}4 m each. Taking point of intersection of these two sides as origin, the magnitude of position vector of the centre of mass of the system is 42x\frac{4 \sqrt{2}}{x}x42​​, where the value of xxx is ‾\underline{\hspace{2cm}}​ .
Numerical answer
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