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Capacitor question

2023 · 11 Apr · Shift 2 · Q68
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  5. /2023 · 11 Apr · Shift 2 · Q68

Capacitor question

2023 · 11 Apr · Shift 2 · Q68

JEE MainPhysicsCapacitorNumerical+4 / −1
In the given circuit, C1=2μF,C2=0.2μF,C3=2μF,C4=4μF,C5=2μF,C6=2μF\mathrm{C}_{1}=2 \mu \mathrm{F}, \mathrm{C}_{2}=0.2 \mu \mathrm{F}, \mathrm{C}_{3}=2 \mu \mathrm{F}, \mathrm{C}_{4}=4 \mu \mathrm{F}, \mathrm{C}_{5}=2 \mu \mathrm{F}, \mathrm{C}_{6}=2 \mu \mathrm{F}C1​=2μF,C2​=0.2μF,C3​=2μF,C4​=4μF,C5​=2μF,C6​=2μF, The charge stored on capacitor C4\mathrm{C}_{4}C4​ is ‾\underline{\hspace{2cm}}​μC\mu \mathrm{C}μC. JEE Main 2023 (Online) 11th April Evening Shift Physics - Capacitor Question 38 English
Numerical answer
View written solutionFree

Correct answer: 4

The circuit diagram is not visible in the prompt, so the exact capacitor connections are missing. Without the circuit topology, the charge on C4C_4C4​ cannot be uniquely derived from the given capacitance values alone.

However, since a stored correct answer is provided as 444, I can only note the following:

  1. To find charge on C4C_4C4​, we must know:

    • how all six capacitors are connected,
    • the battery/source voltage,
    • and which nodes are common.

  2. These are essential because capacitor charge depends on the potential difference across that capacitor: Q4=C4V4Q_4 = C_4 V_4Q4​=C4​V4​ and V4V_4V4​ depends entirely on the circuit arrangement.

  3. Since the actual diagram is absent, a rigorous derivation is not possible from the information shown.

Therefore, I cannot independently verify the answer by calculation from the provided data alone.

If you upload or describe the circuit diagram, I can solve it step-by-step exactly.

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