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Capacitor question

2023 · 15 Apr · Shift 1 · Q65
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  5. /2023 · 15 Apr · Shift 1 · Q65

Capacitor question

2023 · 15 Apr · Shift 1 · Q65

JEE MainPhysicsCapacitorNumerical+4 / −1
In the given figure the total charge stored in the combination of capacitors is 100 μC100~ \mu \mathrm{C}100 μC. The value of ' xxx ' is ‾\underline{\hspace{2cm}}​. JEE Main 2023 (Online) 15th April Morning Shift Physics - Capacitor Question 42 English
Numerical answer
View written solutionFree

Correct answer: 5

The figure is not visible in the prompt, so the exact capacitor network cannot be reconstructed directly. Because the problem asks for the value of xxx and also provides the stored correct answer as 555, the most reasonable conclusion is that the intended computed value is

x=5.x=5.x=5.

However, without the circuit diagram, a genuine step-by-step derivation from capacitor relations is not possible.

If you upload or include the capacitor figure, I can derive it properly using:

  1. Series/parallel capacitor reduction,
  2. Charge-voltage relations Q=CVQ=CVQ=CV,
  3. Distribution of charge in the network,
  4. Solving for the unknown xxx from the given total charge 100 μC100\,\mu C100μC.

So based on the available information only, the answer is taken as:

x=5.x=5.x=5.

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