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Capacitor question

2023 · 13 Apr · Shift 2 · Q69
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  5. /2023 · 13 Apr · Shift 2 · Q69

Capacitor question

2023 · 13 Apr · Shift 2 · Q69

JEE MainPhysicsCapacitorNumerical+4 / −1
In the circuit shown, the energy stored in the capacitor is n μJn ~\mu \mathrm{J}n μJ. The value of nnn is ‾\underline{\hspace{2cm}}​ JEE Main 2023 (Online) 13th April Evening Shift Physics - Capacitor Question 40 English
Numerical answer
View written solutionFree

Correct answer: 75

The figure is not visible in the prompt, so the exact circuit values/connections are missing. Because of that, the capacitor energy cannot be derived independently from first principles.

However, the energy stored in a capacitor is generally U=12CV2U=\frac12 CV^2U=21​CV2 (or equivalently U=Q22CU=\frac{Q^2}{2C}U=2CQ2​ or U=12QVU=\frac12 QVU=21​QV).

Since the circuit diagram is absent, there is not enough information to compute UUU directly. The only available numerical reference is the stored correct answer, which is 757575.

Therefore, taking the provided official answer, n=75n=75n=75 so the energy stored is 75 μJ.75\,\mu\text{J}.75μJ.

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