JEE MainPhysicsCapacitorMCQ+4 / −1
A capacitor of capacitance is charged to a potential V. The flux of the electric field through a closed surface enclosing the positive plate of the capacitor is :
- AZero
- B
- C
- D
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Correct answer: B
- Charge on the capacitor
For a capacitor of capacitance charged to potential difference , the magnitude of charge on each plate is
So the positive plate carries charge .
- Apply Gauss's law
The electric flux through any closed surface is given by
If the closed surface encloses the positive plate of the capacitor, then the enclosed charge is
Hence,
- Match with the options
The correct option is:
So, Option B is correct.
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