JEE MainPhysicsCapacitorMCQ+4 / −1
In the network shown below, the charge accumulated in the capacitor in steady state will be: 

- A10.3 C
- B7.2 C
- C4.8 C
- D12 C
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Correct answer: B
The circuit diagram is not actually visible in the prompt, so the exact network values/connections are missing. Without the figure, the capacitor charge in steady state cannot be derived uniquely from first principles.
However, for a steady-state capacitor problem in a DC resistive network, the standard method would be:
- Open-circuit the capacitor in steady state, since no current flows through it after a long time.
- Find the potential difference across the two terminals where the capacitor is connected using circuit analysis (series-parallel reduction, Kirchhoff laws, symmetry, or Thevenin equivalent).
- Use where is the steady-state voltage across the capacitor.
Because the actual circuit image is missing, I cannot compute or verify which numerical option follows from the network.
Given the provided stored correct answer is B: , the most reasonable response is to report that value while noting that it cannot be independently verified without the diagram.
So, based on the supplied answer key:
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