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Atoms and Nuclei question

2025 · 8 Apr · Shift 2 · Q55
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Atoms and Nuclei question

2025 · 8 Apr · Shift 2 · Q55

JEE MainPhysicsAtoms and NucleiMCQ+4 / −1
For a nucleus of mass number A and radius R, the mass density of nucleus can be represented as
  1. A
    A23A^{\frac{2}{3}}A32​
  2. B
    Independent of A
  3. C
    A3A^3A3
  4. D
    A13A^{\frac{1}{3}}A31​
View written solutionFree

Correct answer: B

  1. Use the nuclear radius relation

    For a nucleus, R=R0A1/3R = R_0 A^{1/3}R=R0​A1/3 where R0R_0R0​ is a constant.

  2. Write the nuclear mass

    Mass of the nucleus is approximately proportional to its mass number: M∝AM \propto AM∝A More specifically, M≈AmnM \approx A m_nM≈Amn​, where mnm_nmn​ is the nucleon mass.

  3. Find the nuclear volume

    Assuming the nucleus is spherical, V=43πR3V = \frac{4}{3}\pi R^3V=34​πR3 Substituting R=R0A1/3R = R_0 A^{1/3}R=R0​A1/3, V=43π(R0A1/3)3=43πR03AV = \frac{4}{3}\pi (R_0 A^{1/3})^3 = \frac{4}{3}\pi R_0^3 AV=34​π(R0​A1/3)3=34​πR03​A So, V∝AV \propto AV∝A

  4. Compute the density

    Density is ρ=MV\rho = \frac{M}{V}ρ=VM​ Since both M∝AM \propto AM∝A and V∝AV \propto AV∝A, ρ∝AA=constant\rho \propto \frac{A}{A} = \text{constant}ρ∝AA​=constant

  5. Conclusion

    The mass density of a nucleus is independent of AAA.

  6. Check options

    • A: A2/3A^{2/3}A2/3 — Incorrect
    • B: Independent of AAA — Correct
    • C: A3A^3A3 — Incorrect
    • D: A1/3A^{1/3}A1/3 — Incorrect

Therefore, the correct answer is: B\boxed{\text{B}}B​

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