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Atoms and Nuclei question

2025 · 24 Jan · Shift 2 · Q60
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Atoms and Nuclei question

2025 · 24 Jan · Shift 2 · Q60

JEE MainPhysicsAtoms and NucleiMCQ+4 / −1
The energy E and momentum p of a moving body of mass m are related by some equation. Given that c represents the speed of light, identify the correct equation
  1. A
    E2=pc2+m2c4\mathrm{E}^2=\mathrm{pc}^2+\mathrm{m}^2 \mathrm{c}^4E2=pc2+m2c4
  2. B
    E2=pc2+m2c2\mathrm{E}^2=\mathrm{pc}^2+\mathrm{m}^2 \mathrm{c}^2E2=pc2+m2c2
  3. C
    E2=p2c2+m2c4\mathrm{E}^2=\mathrm{p}^2 \mathrm{c}^2+\mathrm{m}^2 \mathrm{c}^4E2=p2c2+m2c4
  4. D
    E2=p2c2+m2c2\mathrm{E}^2=\mathrm{p}^2 \mathrm{c}^2+\mathrm{m}^2 \mathrm{c}^2E2=p2c2+m2c2
View written solutionFree

Correct answer: C

  1. Use the relativistic energy-momentum relation

For a particle of rest mass mmm, momentum ppp, and total energy EEE, the correct relation is

E2=p2c2+m2c4E^2 = p^2c^2 + m^2c^4E2=p2c2+m2c4
  1. Check the dimensions of each term
  • E2E^2E2 has dimensions of energy squared.
  • p2c2p^2c^2p2c2 has dimensions: [p]2[c]2=(kg ms)2(ms)2=kg2m4s−4[p]^2[c]^2 = \left(\frac{\text{kg m}}{\text{s}}\right)^2 \left(\frac{\text{m}}{\text{s}}\right)^2 = \text{kg}^2\text{m}^4\text{s}^{-4}[p]2[c]2=(skg m​)2(sm​)2=kg2m4s−4 which is indeed energy squared.
  • m2c4m^2c^4m2c4 also has dimensions of energy squared.

So this formula is dimensionally correct.

  1. Evaluate the options
  • A: E2=pc2+m2c4E^2 = pc^2 + m^2c^4E2=pc2+m2c4
    Incorrect, because the first term should be p2c2p^2c^2p2c2, not pc2pc^2pc2.

  • B: E2=pc2+m2c2E^2 = pc^2 + m^2c^2E2=pc2+m2c2
    Incorrect, both terms are dimensionally wrong.

  • C: E2=p2c2+m2c4E^2 = p^2c^2 + m^2c^4E2=p2c2+m2c4
    Correct.

  • D: E2=p2c2+m2c2E^2 = p^2c^2 + m^2c^2E2=p2c2+m2c2
    Incorrect, the mass term should be m2c4m^2c^4m2c4.

  1. Final answer

The correct equation is

E2=p2c2+m2c4\boxed{E^2 = p^2c^2 + m^2c^4}E2=p2c2+m2c4​

So, the correct option is C.

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