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Atoms and Nuclei question

2025 · 28 Jan · Shift 2 · Q60
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Atoms and Nuclei question

2025 · 28 Jan · Shift 2 · Q60

JEE MainPhysicsAtoms and NucleiMCQ+4 / −1
The frequency of revolution of the electron in Bohr's orbit varies with n, the principal quantum number as:
  1. A
    1n4\frac{1}{n^4}n41​
  2. B
    1n2\frac{1}{n^2}n21​
  3. C
    1n3\frac{1}{n^3}n31​
  4. D
    1n\frac{1}{n}n1​
View written solutionFree

Correct answer: C

  1. In the Bohr model, for the nnnth orbit of hydrogen-like atom:

    rn∝n2r_n \propto n^2rn​∝n2

    and the electron speed varies as

    vn∝1nv_n \propto \frac{1}{n}vn​∝n1​

  2. The frequency of revolution is

    fn=speedcircumference=vn2πrnf_n = \frac{\text{speed}}{\text{circumference}} = \frac{v_n}{2\pi r_n}fn​=circumferencespeed​=2πrn​vn​​

  3. Substitute the dependences on nnn:

    fn∝1/nn2=1n3f_n \propto \frac{1/n}{n^2} = \frac{1}{n^3}fn​∝n21/n​=n31​

  4. Therefore, the frequency of revolution varies as

    fn∝1n3f_n \propto \frac{1}{n^3}fn​∝n31​

  5. Checking options:

    • A: 1n4\frac{1}{n^4}n41​ ❌
    • B: 1n2\frac{1}{n^2}n21​ ❌
    • C: 1n3\frac{1}{n^3}n31​ ✅
    • D: 1n\frac{1}{n}n1​ ❌

Hence, the correct answer is Option C.

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