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Atoms and Nuclei question

2023 · 25 Jan · Shift 1 · Q67
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Atoms and Nuclei question

2023 · 25 Jan · Shift 1 · Q67

JEE MainPhysicsAtoms and NucleiNumerical+4 / −1
The wavelength of the radiation emitted is λ0\lambda_0λ0​ when an electron jumps from the second excited state to the first excited state of hydrogen atom. If the electron jumps from the third excited state to the second orbit of the hydrogen atom, the wavelength of the radiation emitted will 20xλ0\frac{20}{x}\lambda_0x20​λ0​. The value of xxx is ‾\underline{\hspace{2cm}}​.
Numerical answer
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