1. Given data

• Parent nucleus $A$ has mass number: $A = 220$
• Binding energy per nucleon of $A$: $\frac{BE_A}{220} = 5.6\ \text{MeV}$

It splits into two fragments:

• Nucleus $B$ with mass number $105$
• Nucleus $C$ with mass number $115$

So total nucleons after fission: $105+115=220$ which is consistent.

Also, binding energy per nucleon of both fragments is: $6.4\ \text{MeV per nucleon}$

2. Total binding energy of initial nucleus

$BE_{\text{initial}} = 220 \times 5.6$

$BE_{\text{initial}} = 1232\ \text{MeV}$

3. Total binding energy of final fragments

Since each nucleon in the fragments has binding energy $6.4\,\text{MeV}$,

$BE_{\text{final}} = 220 \times 6.4$

$BE_{\text{final}} = 1408\ \text{MeV}$

(Equivalently, $(105\times 6.4) + (115\times 6.4)$ gives the same result.)

4. Energy released in fission

Energy released is the increase in total binding energy:

$Q = BE_{\text{final}} - BE_{\text{initial}}$

$Q = 1408 - 1232$

$Q = 176\ \text{MeV}$

5. Option check

• A: $0.8\,\text{MeV}$ ❌
• B: $275\,\text{MeV}$ ❌
• C: $220\,\text{MeV}$ ❌
• D: $176\,\text{MeV}$ ✅

Final Answer: $\boxed{176\ \text{MeV}}$ So the correct option is D.