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Atoms and Nuclei question

2022 · 26 Jul · Shift 1 · Q71
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Atoms and Nuclei question

2022 · 26 Jul · Shift 1 · Q71

JEE MainPhysicsAtoms and NucleiNumerical+4 / −1
In the hydrogen spectrum, λ\lambdaλ be the wavelength of first transition line of Lyman series. The wavelength difference will be "a λ\lambdaλ'' between the wavelength of 3rd 3^{\text {rd }}3rd  transition line of Paschen series and that of 2nd 2^{\text {nd }}2nd  transition line of Balmer series where a=‾\mathrm{a}=\underline{\hspace{2cm}}a=​.
Numerical answer
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