JEE MainPhysicsAtoms and NucleiMCQ+4 / −1
Taking the wavelength of first Balmer line in hydrogen spectrum (n = 3 to n = 2) as 660 nm, the wavelength of the 2nd Balmer line (n = 4 to n = 2) will be :
- A642.7 nm
- B488.9 nm
- C889.2 nm
- D388.9 nm
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