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Atoms and Nuclei question

2019 · 12 Apr · Shift 1 · Q68
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Atoms and Nuclei question

2019 · 12 Apr · Shift 1 · Q68

JEE MainPhysicsAtoms and NucleiMCQ+4 / −1
An excited He+ ion emits two photons in succession, with wavelengths 108.5 nm and 30.4 nm, in making a transition to ground state. The quantum number n, corresponding to its initial excited state is (for photon of wavelength λ\lambdaλ, energy E=1240 eVλ(in nm)E = {{1240\,eV} \over {\lambda (in\,nm)}}E=λ(innm)1240eV​) :
  1. A
    n = 4
  2. B
    n = 7
  3. C
    n = 5
  4. D
    n = 6
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