Sign in
12thPass logo
New chatPYQ LibraryDoubtsRank report
Sign in to see Recents

Your guest activity stays on this device

Sign in to save progress →
Sign in

Trigonometric Functions and Equations question

2025 · 2 Apr · Shift 2 · Q34
Guest · filters and generic practice availableBrowsing as a guest · PYQ filters and generic practice are available. Sign in only for personalised features and saved progress.
  1. PYQ Library
  2. /JEE Main
  3. /Mathematics
  4. /Trigonometric Functions and Equations
  5. /2025 · 2 Apr · Shift 2 · Q34

Trigonometric Functions and Equations question

2025 · 2 Apr · Shift 2 · Q34

JEE MainMathematicsTrigonometric Functions and EquationsMCQ+4 / −1
If θϵ[−7π6,4π3]\theta \epsilon\left[-\frac{7 \pi}{6}, \frac{4 \pi}{3}\right]θϵ[−67π​,34π​], then the number of solutions of 3cosec⁡2θ−2(3−1)cosec⁡θ−4=0\sqrt{3} \operatorname{cosec}^2 \theta-2(\sqrt{3}-1) \operatorname{cosec} \theta-4=03​cosec2θ−2(3​−1)cosecθ−4=0, is equal to :
  1. A
    7
  2. B
    10
  3. C
    6
  4. D
    8
View written solutionFree

Correct answer: C

  1. Let x=csc⁡θx=\csc\thetax=cscθ Then the equation becomes 3x2−2(3−1)x−4=0\sqrt{3}x^2-2(\sqrt{3}-1)x-4=03​x2−2(3​−1)x−4=0

  2. Solve the quadratic 3x2−2(3−1)x−4=0\sqrt{3}x^2-2(\sqrt{3}-1)x-4=03​x2−2(3​−1)x−4=0

    Using factorization/inspection, test the roots:

    • For x=2x=2x=2: 3(4)−2(3−1)(2)−4=43−43+4−4=0\sqrt{3}(4)-2(\sqrt{3}-1)(2)-4=4\sqrt{3}-4\sqrt{3}+4-4=03​(4)−2(3​−1)(2)−4=43​−43​+4−4=0 So, x=2x=2x=2 is a root.

    Product of roots is −43\frac{-4}{\sqrt{3}}3​−4​ Hence the other root is −4/32=−23\frac{-4/\sqrt{3}}{2}= -\frac{2}{\sqrt{3}}2−4/3​​=−3​2​

    Therefore, csc⁡θ=2orcsc⁡θ=−23\csc\theta=2 \quad \text{or} \quad \csc\theta=-\frac{2}{\sqrt{3}}cscθ=2orcscθ=−3​2​

  3. Convert to sine

    Since csc⁡θ=1sin⁡θ\csc\theta=\dfrac{1}{\sin\theta}cscθ=sinθ1​,

    • If csc⁡θ=2\csc\theta=2cscθ=2, then sin⁡θ=12\sin\theta=\frac12sinθ=21​

    • If csc⁡θ=−23\csc\theta=-\frac{2}{\sqrt{3}}cscθ=−3​2​, then sin⁡θ=−32\sin\theta=-\frac{\sqrt{3}}{2}sinθ=−23​​

  4. Find all solutions in θ∈[−7π6,4π3]\theta\in\left[-\frac{7\pi}{6},\frac{4\pi}{3}\right]θ∈[−67π​,34π​]


    Case 1: sin⁡θ=12\sin\theta=\dfrac12sinθ=21​

    General solutions: θ=π6+2kπorθ=5π6+2kπ\theta=\frac{\pi}{6}+2k\pi \quad \text{or} \quad \theta=\frac{5\pi}{6}+2k\piθ=6π​+2kπorθ=65π​+2kπ

    Now check values in the interval [−7π6,4π3]\left[-\frac{7\pi}{6},\frac{4\pi}{3}\right][−67π​,34π​]:

    • From θ=π6+2kπ\theta=\frac{\pi}{6}+2k\piθ=6π​+2kπ: θ=π6\theta=\frac{\pi}{6}θ=6π​ is in the interval. π6−2π=−11π6\frac{\pi}{6}-2\pi=-\frac{11\pi}{6}6π​−2π=−611π​ is not in the interval.

    • From θ=5π6+2kπ\theta=\frac{5\pi}{6}+2k\piθ=65π​+2kπ: θ=5π6\theta=\frac{5\pi}{6}θ=65π​ is in the interval. 5π6−2π=−7π6\frac{5\pi}{6}-2\pi=-\frac{7\pi}{6}65π​−2π=−67π​ is also in the interval.

    So this case gives 3 solutions: θ=−7π6, π6, 5π6\theta=-\frac{7\pi}{6},\ \frac{\pi}{6},\ \frac{5\pi}{6}θ=−67π​, 6π​, 65π​


    Case 2: sin⁡θ=−32\sin\theta=-\dfrac{\sqrt{3}}{2}sinθ=−23​​

    General solutions: θ=−π3+2kπorθ=−2π3+2kπ\theta=-\frac{\pi}{3}+2k\pi \quad \text{or} \quad \theta=-\frac{2\pi}{3}+2k\piθ=−3π​+2kπorθ=−32π​+2kπ

    Check values in the interval:

    • From θ=−π3+2kπ\theta=-\frac{\pi}{3}+2k\piθ=−3π​+2kπ: −π3-\frac{\pi}{3}−3π​ is in the interval, −π3+2π=5π3-\frac{\pi}{3}+2\pi=\frac{5\pi}{3}−3π​+2π=35π​ is not, −π3−2π=−7π3-\frac{\pi}{3}-2\pi=-\frac{7\pi}{3}−3π​−2π=−37π​ is not.

    • From θ=−2π3+2kπ\theta=-\frac{2\pi}{3}+2k\piθ=−32π​+2kπ: −2π3-\frac{2\pi}{3}−32π​ is in the interval, −2π3+2π=4π3-\frac{2\pi}{3}+2\pi=\frac{4\pi}{3}−32π​+2π=34π​ is in the interval, −2π3−2π=−8π3-\frac{2\pi}{3}-2\pi=-\frac{8\pi}{3}−32π​−2π=−38π​ is not.

    So this case gives 3 solutions: θ=−2π3, −π3, 4π3\theta=-\frac{2\pi}{3},\ -\frac{\pi}{3},\ \frac{4\pi}{3}θ=−32π​, −3π​, 34π​

  5. Total number of solutions 3+3=63+3=63+3=6

  6. Compare with options The correct option is: C: 6\boxed{\text{C: }6}C: 6​

  7. Verification with stored answer Stored correct answer is C, which matches our result.

PreviousNext

More from Trigonometric Functions and Equations

  •  The number of solutions of the equation 2x+3tanx=π,x∈[−2π,2π]−{±2π​,±23π​} is: 2025 · MCQ
  • The number of solutions of the equation (4−3​)sinx−23​cos2x=−1+3​4​,x∈[−2π,25π​] is2025 · MCQ
  • The number of solutions of the equation cos2θcos2θ​+cos25θ​=2cos325θ​ in [−2π​,2π​] is :2025 · MCQ
  • The sum of all values of θ∈[0,2π] satisfying 2sin2θ=cos2θ and 2cos2θ=3sinθ is2025 · MCQ
  • The number of solutions of the equation 4sin2x−4cos3x+9−4cosx=0;x∈[−2π,2π] is :2024 · MCQ
  • Let S={sin22θ:(sin4θ+cos4θ)x2+(sin2θ)x+(sin6θ+cos6θ)=0 has real roots }. If α and β be the smallest and largest elements of the…2024 · Numerical
  • The number of solutions of sin2x+(2+2x−x2)sinx−3(x−1)2=0, where −π≤x≤π, is ​.2024 · Numerical
  • Let ∣cosθcos(60−θ)cos(60+θ)∣≤81​,θϵ[0,2π]. Then, the sum of all θ∈[0,2π], where cos3θ attains its maximum value, is :2024 · MCQ