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Trigonometric Functions and Equations question
2025 · 2 Apr · Shift 1 · Q29
JEE MainMathematicsTrigonometric Functions and EquationsMCQ+4 / −1
If θ∈[−2π,2π], then the number of solutions of 22cos2θ+(2−6)cosθ−3=0, is equal to:
A
8
B
6
C
10
D
12
View written solutionFree
Correct answer: A
Letx=cosθ. Then the equation becomes
22x2+(2−6)x−3=0.
We must first solve this quadratic for x, and then count how many θ∈[−2π,2π] satisfy cosθ=x.
Factor the quadratic.
We look for a factorization of the form
22x2+(2−6)x−3=(ax+b)(cx+d).
Try
(2x+3)(2x−1).
Expanding:
(2x+3)(2x−1)=22x2−2x+23x−3.
Now,
−2+23=2−6?
Let us instead try
(2x−3)(2x+1).
Expanding:
(2x−3)(2x+1)=22x2+2x−23x−3
so the coefficient of x is
2−23.
This is not equal to 2−6 directly. So we solve using the quadratic formula.
Use the quadratic formula for
22x2+(2−6)x−3=0.
Here,
a=22,b=2−6,c=−3.
Then
x=2⋅22−(2−6)±(2−6)2−4(22)(−3).
Compute the discriminant:
(2−6)2+86=4+6−46+86=10+46.
Notice that
10+46=(2+6)2.
So
10+46=2+6.
Hence
x=42−2+6±(2+6).
Thus the two roots are:
With + sign:
x=42−2+6+2+6=4226=23.
With − sign:
x=42−2+6−2−6=42−4=−21=−22.
So the equation reduces to
cosθ=23orcosθ=−22.
Count solutions forcosθ=23 in [−2π,2π].
General angles are
θ=2kπ±6π.
List those in [−2π,2π]:
−611π,−6π,6π,611π.
So there are 4 solutions.
Count solutions forcosθ=−22 in [−2π,2π].
General angles are
θ=2kπ±43π.
List those in [−2π,2π]:
−45π,−43π,43π,45π.
So there are 4 solutions.
Total number of solutions:
4+4=8.
Therefore, the correct option is
A: 8.
Comparison with stored answer:
Stored correct answer is A, which matches our derived answer.