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Probability question

2020 · 9 Jan · Shift 2 · Q34
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  5. /2020 · 9 Jan · Shift 2 · Q34

Probability question

2020 · 9 Jan · Shift 2 · Q34

JEE MainMathematicsProbabilityMCQ+4 / −1
A random variable X has the following probability distribution :

X: 1 2 3 4 5
P(X): K2 2K K 2K 5K2

Then P(X > 2) is equal to :
  1. A
    16{1 \over {6}}61​
  2. B
    712{7 \over {12}}127​
  3. C
    136{1 \over {36}}361​
  4. D
    2336{23 \over {36}}3623​
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