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Limits Continuity and Differentiability question

2024 · 31 Jan · Shift 2 · Q56
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  5. /2024 · 31 Jan · Shift 2 · Q56

Limits Continuity and Differentiability question

2024 · 31 Jan · Shift 2 · Q56

JEE MainMathematicsLimits Continuity and DifferentiabilityNumerical+4 / −1
If lim⁡x→0ax2ex−blog⁡e(1+x)+cxe−xx2sin⁡x=1\lim_{x \rightarrow 0} \frac{a x^2 e^x-b \log _e(1+x)+c x e^{-x}}{x^2 \sin x}=1x→0lim​x2sinxax2ex−bloge​(1+x)+cxe−x​=1, then 16(a2+b2+c2)16\left(a^2+b^2+c^2\right)16(a2+b2+c2) is equal to ‾\underline{\hspace{2cm}}​.
Numerical answer
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