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Limits Continuity and Differentiability question

2020 · 5 Sep · Shift 1 · Q23
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  5. /2020 · 5 Sep · Shift 1 · Q23

Limits Continuity and Differentiability question

2020 · 5 Sep · Shift 1 · Q23

JEE MainMathematicsLimits Continuity and DifferentiabilityMCQ+4 / −1
If α\alphaα is positive root of the equation, p(x) = x2 - x - 2 = 0, then lim⁡x→α+1−cos⁡(p(x))x+α−4\mathop {\lim }\limits_{x \to {\alpha ^ + }} {{\sqrt {1 - \cos \left( {p\left( x \right)} \right)} } \over {x + \alpha - 4}}x→α+lim​x+α−41−cos(p(x))​​ is equal to :
  1. A
    12{1 \over \sqrt2}2​1​
  2. B
    12{1 \over 2}21​
  3. C
    32{3 \over \sqrt2}2​3​
  4. D
    32{3 \over 2}23​
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