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Limits Continuity and Differentiability question

2020 · 2 Sep · Shift 1 · Q28

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JEE Main
Mathematics
Limits Continuity and Differentiability
2020 · 2 Sep · Shift 1 · Q28

Limits Continuity and Differentiability question

2020 · 2 Sep · Shift 1 · Q28

JEE MainMathematicsLimits Continuity and DifferentiabilityNumerical+4 / −1

If

\mathop {\lim }\limits_{x \to 1} {{x + {x^2} + {x^3} + ... + {x^n} - n} \over {x - 1}}

= 820, (n

\in

N) then the value of n is equal to

\underline{\hspace{2cm}}

.

Numerical answer

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