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Limits Continuity and Differentiability question

2019 · 10 Jan · Shift 1 · Q30
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  5. /2019 · 10 Jan · Shift 1 · Q30

Limits Continuity and Differentiability question

2019 · 10 Jan · Shift 1 · Q30

JEE MainMathematicsLimits Continuity and DifferentiabilityMCQ+4 / −1
For each t ∈\in∈ R , let [t] be the greatest integer less than or equal to t Then lim⁡x→1+(1−∣x∣+sin⁡∣1−x∣)sin⁡(π2[1−x])∣1−x∣.[1−x]\mathop {\lim }\limits_{x \to 1^ + } {{\left( {1 - \left| x \right| + \sin \left| {1 - x} \right|} \right)\sin \left( {{\pi \over 2}\left[ {1 - x} \right]} \right)} \over {\left| {1 - x} \right|.\left[ {1 - x} \right]}}x→1+lim​∣1−x∣.[1−x](1−∣x∣+sin∣1−x∣)sin(2π​[1−x])​
  1. A
    equals −-− 1
  2. B
    equals 1
  3. C
    equals 0
  4. D
    does not exist
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