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Limits Continuity and Differentiability question

2019 · 11 Jan · Shift 1 · Q36
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  5. /2019 · 11 Jan · Shift 1 · Q36

Limits Continuity and Differentiability question

2019 · 11 Jan · Shift 1 · Q36

JEE MainMathematicsLimits Continuity and DifferentiabilityMCQ+4 / −1
Let f(x)={−1−2≤x<0x2−1,0≤x≤2f\left( x \right) = \left\{ {\begin{matrix} { - 1} & { - 2 \le x \lt 0} \\ {{x^2} - 1,} & {0 \le x \le 2} \\ \end{matrix} } \right.f(x)={−1x2−1,​−2≤x<00≤x≤2​ and g(x)=∣f(x)∣+f(∣x∣).g(x) = \left| {f\left( x \right)} \right| + f\left( {\left| x \right|} \right).g(x)=∣f(x)∣+f(∣x∣). Then, in the interval (–2, 2), g is :
  1. A
    non continuous
  2. B
    differentiable at all points
  3. C
    not differentiable at two points
  4. D
    not differentiable at one point
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