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Limits Continuity and Differentiability question

2019 · 11 Jan · Shift 2 · Q30
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  5. /2019 · 11 Jan · Shift 2 · Q30

Limits Continuity and Differentiability question

2019 · 11 Jan · Shift 2 · Q30

JEE MainMathematicsLimits Continuity and DifferentiabilityMCQ+4 / −1
lim⁡x→0xcot⁡(4x)sin⁡2xcot⁡2(2x)\mathop {\lim }\limits_{x \to 0} {{x\cot \left( {4x} \right)} \over {{{\sin }^2}x{{\cot }^2}\left( {2x} \right)}}x→0lim​sin2xcot2(2x)xcot(4x)​ is equal to :
  1. A
    0
  2. B
    4
  3. C
    1
  4. D
    2
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