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Limits Continuity and Differentiability question

2019 · 12 Apr · Shift 2 · Q31

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JEE Main
Mathematics
Limits Continuity and Differentiability
2019 · 12 Apr · Shift 2 · Q31

Limits Continuity and Differentiability question

2019 · 12 Apr · Shift 2 · Q31

JEE MainMathematicsLimits Continuity and DifferentiabilityMCQ+4 / −1

Let f(x) = 5 – |x – 2| and g(x) = |x + 1|, x

\in

R. If f(x) attains maximum value at

\alpha

and g(x) attains minimum value at

\beta

, then

\mathop {\lim }\limits_{x \to -\alpha \beta } {{\left( {x - 1} \right)\left( {{x^2} - 5x + 6} \right)} \over {{x^2} - 6x + 8}}

is equal to :

A
${1 \over 2}$
B
$-{1 \over 2}$
C
${3 \over 2}$
D
$-{3 \over 2}$

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