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Indefinite Integrals question

2024 · 29 Jan · Shift 1 · Q43
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  5. /2024 · 29 Jan · Shift 1 · Q43

Indefinite Integrals question

2024 · 29 Jan · Shift 1 · Q43

JEE MainMathematicsIndefinite IntegralsMCQ+4 / −1
For x∈(−π2,π2)x \in\left(-\frac{\pi}{2}, \frac{\pi}{2}\right)x∈(−2π​,2π​), if y(x)=∫cosec⁡x+sin⁡xcosec⁡xsec⁡x+tan⁡xsin⁡2xdxy(x)=\int \frac{\operatorname{cosec} x+\sin x}{\operatorname{cosec} x \sec x+\tan x \sin ^2 x} d xy(x)=∫cosecxsecx+tanxsin2xcosecx+sinx​dx, and lim⁡x→(π2)−y(x)=0\lim_{x \rightarrow\left(\frac{\pi}{2}\right)^{-}} y(x)=0x→(2π​)−lim​y(x)=0 then y(π4)y\left(\frac{\pi}{4}\right)y(4π​) is equal to
  1. A
    −12tan⁡−1(12)-\frac{1}{\sqrt{2}} \tan ^{-1}\left(\frac{1}{\sqrt{2}}\right)−2​1​tan−1(2​1​)
  2. B
    tan⁡−1(12)\tan ^{-1}\left(\frac{1}{\sqrt{2}}\right)tan−1(2​1​)
  3. C
    12tan⁡−1(12)\frac{1}{2} \tan ^{-1}\left(\frac{1}{\sqrt{2}}\right)21​tan−1(2​1​)
  4. D
    12tan⁡−1(−12)\frac{1}{\sqrt{2}} \tan ^{-1}\left(-\frac{1}{2}\right)2​1​tan−1(−21​)
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