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Indefinite Integrals question

2023 · 8 Apr · Shift 1 · Q32
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Indefinite Integrals question

2023 · 8 Apr · Shift 1 · Q32

JEE MainMathematicsIndefinite IntegralsMCQ+4 / −1
Let I(x)=∫(x+1)x(1+xex)2dx,x>0I(x)=\int \frac{(x+1)}{x\left(1+x e^{x}\right)^{2}} d x, x \gt 0I(x)=∫x(1+xex)2(x+1)​dx,x>0. If lim⁡x→∞I(x)=0\lim_{x \rightarrow \infty} I(x)=0x→∞lim​I(x)=0, then I(1)I(1)I(1) is equal to :
  1. A
    e+1e+2−log⁡e(e+1)\frac{e+1}{e+2}-\log _{e}(e+1)e+2e+1​−loge​(e+1)
  2. B
    e+1e+2+log⁡e(e+1)\frac{e+1}{e+2}+\log _{e}(e+1)e+2e+1​+loge​(e+1)
  3. C
    e+2e+1−log⁡e(e+1)\frac{e+2}{e+1}-\log _{e}(e+1)e+1e+2​−loge​(e+1)
  4. D
    e+2e+1+log⁡e(e+1)\frac{e+2}{e+1}+\log _{e}(e+1)e+1e+2​+loge​(e+1)
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